Question

In problem 20, it was stated that the ideal air-to-fuel ratio for an engine is 14.7:1. If a vehicle burns 9 lb of fuel, how many pounds of air should it draw to achieve the ideal ratio? (Round to the nearest pound.)

Answer 1

132 pounds of air.

Step-by-step explanation:

The ideal air-to-fuel ratio for an engine = 14.7 : 1

The number of pounds of fuel burned by the vehicle = 9 lb

Let the pounds of air drawn to achieve this ratio = x

Then, we have:

`\frac{\text{Air}}{\text{Fuel}}\colon(14.7)/(1)=(x)/(9)`

Next, solve the equation above for x:

`\begin{gathered} x=9*14.7 \\ x=132.3\text{ lb} \\ x\approx132\; lb \end{gathered}`

To the nearest pound, the vehicle should draw 132 pounds of air.