equation of the line that passes through (3, 2) and (9.-2)
step 1
Find the slope
m=(-2-2)/(9-3)
m=-4/6
simplify
m=-2/3
step 2
Find the equation of the line in point slope form
y-y1=m(x-x1)
we have
m=-2/3
(x1,y1)=(3,2)
substitute
y-2=(-2/3)(x-3) ------> equation in point slope form
step 3
Find the equation of the line in slope intercept form
y=mx+b
we have
y-2=(-2/3)(x-3)
isolate the variable y
y-2=-(2/3)x+2
y=-(2/3)x+2+2
y=-(2/3)x+4 ------> equation in slope intercept form
step 4
Find the equation in standard form
Ax+By=C
wgere
A is a positive integer
B and C are integers
we have
y=-(2/3)x+4
Multiply by 3 both sides
3y=-2x+12
rewrite
2x+3y=12 ------> equation in standard form