Question

In the lab, Maya has two solutions that contain alcohol and is mixing them with each other. She uses twice as much solution A as solution B, solution A is 14% alcohol and solution B is 11% alcohol. How many millimeters of solution B does she use, if the resulting mixture has 78 milliliters of pure alcohol?

Answer 1

Maya uses 200 millimeters of solution B.

Step-by-step explanation

Let the amount of the first solution mixed be A

Let the amount of the second solution mixed be B

First solution is 14% alcohol

Alcohol content = 0.14A

Second solution is 11%

Alcohol content = 0.11B

She uses twice as much solution A as solution B

A = 2B

Resulting mixture = A + B

Alcohol content in resulting mixture = 0.14A + 0.11B = 78

Recall, A = 2B

0.14A + 0.11B = 78

0.14(2B) + 0.11B = 78

0.28B + 0.11B = 78

0.39B = 78

Divide both sides by 0.39

(0.39B/0.39) = (78/0.39)

B = 200 millimeters

A = 2B = 2(200) = 400 millimeters

Hope this Helps!!!