Question

Can some one plz help me

Answer 1

AB = BA reflexive property

AB = BE and DA = AB definition of midpoint

then DA = EB

CD = CE ΔCDE is isosceles

ΔCDA ≅ ΔCEB SAS

Explanation:

Answer 2

Explanation:

A is midpoint of DB

DA ≅ AB ------------------(I)

B is midpoint of AE

BE≅ AB ---------------(II)

From (I) & (II)

DA ≅ AB

∠D ≅ ∠E Given

CD ≅ CE {Sides opposite to equal angles are equal}

ΔCDA ≅ ΔCEB { S A S congruent}