In this question, we need to find the slope and y-intercept.
The standard slope-intercept form is:
y = mx + b
Here, m is the slope that is the difference of y values over x values.
b is y-intercept or the value of y where x is zero.
Now map the given equation with the standard equation, we get
y = mx + b. <=> y = 3/2x
hence,
m = 3/2
b = 0, that means the y-intercept is at origan (0, 0).
Now, simply fecth the values of y by placing the values in the given equation.
for x = 1
y = 3/2(x) = 3/2(1) = 3/2 = (1, 3/2)
for x = 2
y = 3/2(x) = 3/2(2) = 3 = (2, 3)
for x = 3
y = 3/2(x) = 3/2(3) = 3/2 = (3, 9/2)
Similarly, you can generate ordered pairs for negative x values and plot the graph. '