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What is the angle of elevation to the nearest tenth of a degree to the top of a 35-ft building from 75 ft away?angle of elevation

User SolidSmile
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1 Answer

4 votes

Using the information given in the exercise, you can draw the following Right triangle (It is not drawn to scale).

Where the angle of elevarion is β.

Then, you can use the following Inverse trigonometric function:


\beta=\tan ^(-1)((opposite)/(adjacent))

In this case:


\begin{gathered} opposite=35 \\ adjacent=75 \end{gathered}

Substituting values into the Inverse trigonometric function and evaluating, you get:


\begin{gathered} \beta=\tan ^(-1)((35)/(75)) \\ \\ \beta\approx25.0\degree \end{gathered}

The answer is:


25.0\degree

What is the angle of elevation to the nearest tenth of a degree to the top of a 35-ft-example-1
User Michel Milezzi
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