Given
![y=(1)/(2)\cdot\sin(4\theta)](https://img.qammunity.org/2023/formulas/mathematics/college/fhu6bth135q0alr4u70w86rghnuaoyv81g.png)
Find
Amplitude and period of the function and graph it.
Step-by-step explanation
the amplitude of the function is the largest value that the given function may attain. the amplitude of the given function is 1/2.
to find the period of the function , divide 2pi by the coefficient of theta
here , the coefficient of theta is 4 .
so , the period =
![\begin{gathered} (2\pi)/(4) \\ \\ (\pi)/(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/559efgi8rvyvo27eblfpvmrarh2g2e499i.png)
given function has an amplitude of 1/2 and period of pi/2.
now , we graph the function.
the graph completed one period in the interval
![0\leq\theta\leq(\pi)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/kui79ptfz9hhlr8bsn2lr4xrifdu0rmmfe.png)
that an effect of shrinking the graph horizontally,
Final Answer
The graph will be made as shown