Question

Determine an equation for the line that has a y- intercept 8 of an x intercept of -2 ?

Answer 1

Given:

y-intercept = 8

x-intercept = -2

At y-intercept, x = 0: (0, 8)

At x intercept, y = 0: (-2, 0)

Use the slope intercept form:

y = mx + b

Where m is the slope and b is the y-intercept

To find an equation for the line, first find the slope.

`m=(y2-y1)/(x2-x1)`

Where

(x1, y1) ==> (-2, 0)

(x2, y2) ==> (0, 8)

`m=(8-0)/(0--2)=(8)/(0+2)=(8)/(2)=4`

The slope is 4

The y-intercept = 8

We have:

y = 4x + b

Therefore, the equation of the line is:

y = 4x + 8

ANSWER:

y = 4x + 8