Question

`\frac{( {2a}^(3) )( {10a}^(5) )}{ {4a}^( - 1) }`negative and zero exponents

Answer 1

`\begin{gathered} \frac{( {2a}^(3) )( {10a}^(5) )}{ {4a}^( - 1) }=((2\cdot10)(a^3a^5))/(4)a \\ =(20a^(3+5)a)/(4) \\ =(20)/(4)a^8a \\ =5a^(8+1) \\ =5a^9 \end{gathered}`