\frac{( {2a}^(3) )( {10a}^(5) )}{ {4a}^( - 1) }negative and zero exponents

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asked Sep 20, 2023 89.0k views

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$\frac{( {2a}^(3) )( {10a}^(5) )}{ {4a}^( - 1) }$ negative and zero exponents

Mathematics
college

Ed Webb asked

by Ed Webb

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$\begin{gathered} \frac{( {2a}^(3) )( {10a}^(5) )}{ {4a}^( - 1) }=((2\cdot10)(a^3a^5))/(4)a \\ =(20a^(3+5)a)/(4) \\ =(20)/(4)a^8a \\ =5a^(8+1) \\ =5a^9 \end{gathered}$

Fdorssers answered Sep 27, 2023

by Fdorssers

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