Question

A rocket car experiences an acceleration of 10.0 m/s2. If the car starts from rest, how far will it travel in the first 5.00 sec ?

Answer 1

We will have the following:

We remember that the distance for a linear accelerated motion is given by the expression:

`d=v_it+(1)/(2)at^2`

Here "d" is the distance, "vi" is the initial velocity (In our case it starts at rest so 0 m/s), "t" is the time and "a" is the acceleration at which the object is subjected, so:

`d=(0m/s)(5.00s)+(1)/(2)(10.0m/s^2)(5.00s)^2\Rightarrow d=125.0m`

So, the distance the car travels in those 5 seconds is 125.0 m.