Given isosceles right triangle CDE with m∠D = 90, sin C = sin D

Veena asked Feb 24, 2022

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Veena asked Feb 24, 2022

by Veena

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23 votes

Answer:True

Explanation:

Given

$\angle D=90^(\circ)$

For isosceles triangle , CD=DE (x=y)

from figure,

$\sin C=(y)/(H)\\\\\sin D=(x)/(H)\\\\\text{CD=DE}\\\\\therefore \sin C=\sin D=(x)/(H)=(y)/(H)$

Thus, the given statement is true

Ivan Smirnov answered Mar 3, 2022

2.8k points

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