We must find the maximum of the following function:
![P(x)=-4x^2+8x+4.](https://img.qammunity.org/2023/formulas/mathematics/college/cng49m38rc7fi2fzsdmsg5mjsm4u7cjzrx.png)
To find the maximum, we equal to zero the first derivative of P(x):
![P^(\prime)(x)=-4\cdot2x+8=0,](https://img.qammunity.org/2023/formulas/mathematics/college/15yxsg32pv4ybw0ylabp21a3lidta14q4u.png)
and then we solve for x:
![\begin{gathered} -4\cdot2x+8=0, \\ -8x+8=0, \\ 8x=8, \\ x=(8)/(8)=1. \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/x1wnajs2u590guelpz4uka23np88qhmlnk.png)
Now, we evaluate the function for x = 1, we get:
![P(1)=-4\cdot1^2+8\cdot1+4=8.](https://img.qammunity.org/2023/formulas/mathematics/college/s89ivcwhr13xa4p2sfi8uuhy7a7zjgcfm3.png)
From the statement we know that:
• x is the number of units produced per week, in thousands,
,
• P(x) is the weekly profit, in hundreds of dollars.
So the maximum is reached for 1,000 units and the profit is $800 in that case.
Answer
b. 1,000 units; $800