Question

calculate Fe between two electrons and two protons respectively. the distance between charges is 5 x 10 exp-2 m

Answer 1

Given,

The distance between the charges is r=5×10⁻² m

From Coulomb's law, the force between two charges is given by,

`F_e=(kq_1q_2)/(r^2)`

Where k is the coulomb's constant, q₁ and q₂ are the charges.

The magnitude of the charge of proton and electron is q=1.6×10⁻¹⁹ C

Thus the force between the two electrons and two protons is,

`\begin{gathered} F_e=(9*10^(-9)*1.6*10^(-19)*1.6*10^(-19))/((5*10^(-2))^2) \\ =9.22*10^(-26)\text{ N} \end{gathered}`

Thus the force between two electrons and two protons respectively is 9.22×10⁻²⁶ N