Question

Identify the height of a triangle in which b=(x−2) m and A=(x2−4) m2.(please help)

Answer 1

Given -

Base = (x−2) m

Area = (x²−4) m²

To Find -

Height =?

Step-by-Step Explanation -

We know the formula for:

`\begin{gathered} Area\text{ of Triangle = }(1)/(2)* Base* Height \\ \\ (x^2-2^2)\text{ = }(1)/(2)*(x-2)* Height \\ \\ (x+2)(x-2)\text{ = }(1)/(2)*(x-2)* Height\text{ \lparen as a}^2-b^2=(a+b)(a-b)\text{\rparen} \\ \\ Height\text{ = 2\lparen x+2\rparen} \end{gathered}`

Final Answer -

Height = 2(x+2) m = 2x + 4 m