The given system of equations is expressed as
5x = y + 37
x = - 5y - 29
We would apply the method of substitution by substituting equation 2 into equation1. It becomes
5(- 5y - 29) = y + 37
- 25y - 145 = y + 37
y + 25y = - 145 - 37
26y = - 182
y = - 182/26
y = - 7
Substituting y = - 7 into the second equation, it becomes
x = - 5 * - 7 - 29
x = 35 - 29
x = 6
The solution is (6, - 7)