Question

1. Inte the size of angle Mae a fraction, Then we decimal rounded to the 8-20

Answer 1

In the given right triangle LMN

N is the right angle, then LM is the hypotenuse

For angle M

The opposite side to it is LN

Then

`\sin M=(LN)/(LM)`

LN = 8 and LM = 10

`\sin M=(8)/(10)=(4)/(5)`

The adjacent side is NM

`\cos M=(NM)/(LM)`

NM = 5 and LM = 10

`\cos M=(5)/(10)=(1)/(2)`

For angle L

The opposite side is MN

`\sin L=(MN)/(LM)`
`\sin L=(5)/(10)=(1)/(2)`

The adjacent side is LN

`\cos L=(LN)/(LM)`
`\cos L=(8)/(10)=(4)/(5)`

From the answers above

Sin M = 4/5 and cos L = 4/5, then

5) sin M is equal to cos L

and also cos M = sin L