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Select the atoms whose ions have an electron configuration of nd^6 (n = 3, 4, 5 ...). For example, the 2+ ion for V ends the electron configuration with 3d^3 .Check all that apply.A. Tl B. Fe C. Rh D. La E. Os F. Ti

User Sealocal
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Answer

Correct answers are B. Fe and E. Os

Step-by-step explanation

For Fe: electron configuration for Fe is


[Ar]3d^64s^2

For TI: the electron configuration is


[Xe]4f^(14)5d^(10)6s^26p^1

For Rh: Electron configuration of Rhodium is


[Kr]4d^85s^1

For La: Electron configuration of Lanthanum is


[Xe]5d^16s^2

For Os: Electron configuration is


[Xe]4f^(14)5d^66s^1

For Ti: Electron configuration is


[Ar]3d^24s^2

User Valeriane
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