Question

2.Solve the given equation over the interval [0, 2.x): 2 sin2 x - sin x = 0.7% 11%x= 0 and x= and x=662 20x = 0 and x= - and x =3ग57x = 0 and x = - and x =664557x= 0 and x=and x =33

Answer 1

It is given that

`\begin{gathered} 2\sin ^2x-\sin x=0 \\ \sin x(2\sin x-1)=0 \\ \sin x=0,2\sin x-1=0 \\ \sin x=0,\sin x=(1)/(2) \end{gathered}`

Therefore in the interval

`\lbrack0,2\pi)`

sin function takes the value 0 at

`x=0,x=\pi`

It takes the value of 0.5 at

`x=(\pi)/(6),(5\pi)/(6)`

Therefore the above four values are correct

Option C is correct.