Question

A 62.92 microC charge is fixed at the origin. How much work would be required to place a 7.21 microC charge 8.57 cm from this charge ?

Answer 1

Given

The fixed charge is q=62.92 mC

The other charge is q'=7.21 mC

The distance is r=8.57 cm=0.0857 m

To find

The work done

Step-by-step explanation

The potential is

`\begin{gathered} V=(kq)/(r) \\ \Rightarrow V=9*10^9(62.92*10^(-6))/(0.0857) \\ \Rightarrow V=6.6*10^6V \end{gathered}`

Work done is

`\begin{gathered} W=q^(\prime)V \\ \Rightarrow W=7.21*10^(-6)*6.6*10^6=47.586\text{ J} \end{gathered}`

Conclusion

The work done is 47.586 V