Let the price of a bike at Store B be k
The price of a bike at Store A is 5/6 of the price at store B, which means
![=(5)/(6)* k=(5k)/(6)](https://img.qammunity.org/2023/formulas/mathematics/college/c2tr0lh4qaa9xoihn78vg4gkj87zbqfkpd.png)
If the price of a bike at Store A is $150.60, i.e
![(5k)/(6)=150.60](https://img.qammunity.org/2023/formulas/mathematics/college/u683hhhch1t9jd1qjn7q64rzj7nzpdc5qi.png)
Solve to find k, i.e the price of a bike at Store B
Crossmultiply
![\begin{gathered} (5k)/(6)=150.60 \\ 5k=150.60*6=903.6 \\ 5k=903.6 \\ \text{Divide both sides by 5} \\ (5k)/(5)=(903.6)/(5) \\ k=\text{ \$180.72} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/cwcv6b2q5z73abrkded1eju4zrjmp9k49z.png)
The price of a bike at store B is k = $180.72
The amount saved if the bike is bought at Store A is
![=180.72-150.60=\text{ \$30.12}](https://img.qammunity.org/2023/formulas/mathematics/college/u9s5zdzhmg16qkjplecxl965h4tvf9x4la.png)
Hence, the amount saved by buying the bike at Store A is $30.12