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If 180 kg of sugar is to be divided into 3 quantities of ratio 2:3:4 find the smallest and largest quantities.​

2 Answers

11 votes
  • Ratios be 2x ,3x,4x


\\ \tt\hookrightarrow 2x+3x+4x=180


\\ \tt\hookrightarrow 9x=180


\\ \tt\hookrightarrow x=20

  • 2x=40
  • 4x=80
User Arpit Srivastava
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5.0k points
11 votes

Answer:

smallest amount of sugar = 40 kg

largest amount of sugar = 80 kg

Explanation:

2 : 3 : 4

2 + 3 + 4 = 9

180 ÷ 9 = 20

Therefore,

2 : 3 : 4 = (2 x 20) : (3 x 20) : (4 x 20) = 40 : 60 : 80

So the smallest amount of sugar = 40 kg

and the largest amount of sugar = 80 kg

User Cody Brimhall
by
4.4k points