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A rock against the frictionless inside wall of a cone with a radius of 2 meters. It moves with the cone with a constant speed of 6m/s. The rock does not slide up or down in the cone as it rotates what is the centripetal acceleration of the rock

User NoLifeKing
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Answer:

Centripetal acceleration of the rock is 18 m/s²

Step-by-step explanation:

According to the question,

Radius (r) of frictionless wall inside cone is 2 meters

Rock moves with a constant speed (v)of 6 m/s

As rock does not slide up or down in the cone as it rotates so it's centripetal acceleration can be calculated as follows:


\rm \implies a_c = (v^2)/(r) \\ \\ \rm \implies a_c = \frac{ {6}^(2) }{2} \\ \\ \rm \implies a_c = (36)/(2) \\ \\ \rm \implies a_c = 18 \: m {s}^( - 2)

User Iliaden
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