Question

A circuit with a 23 V battery and two 15 Ω resistors in series. What is the current throughout the circuit?

Answer 1

V = 23V

R1 = 15 Ω

R2= 15 Ω

Both resistors in series

Rt = total resistance = R1 + R2 = 15 + 15 = 30Ω

Ohm's law:

V = I x R

I = V/R = 23V/30Ω= 0.766 Ampere

Current = 0.766 A