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Given : XB bisects ABC m < 1 = 4x + 5 m < 2 = 5x - 2

Given : XB bisects ABC m < 1 = 4x + 5 m < 2 = 5x - 2
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Given : XB bisects ABC m < 1 = 4x + 5 m < 2 = 5x - 2

Given : XB bisects ABC m < 1 = 4x + 5 m < 2 = 5x - 2-example-1
User Deltab
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\begin{gathered} \text{ Since XB bisects the triangle, the angles 1 and 2 must be equal, that is} \\ 4x+5=5x-2 \\ 4x+5+2=5x \\ 4x+7=5x \\ 7=5x-4x \\ 7=x \\ \\ x=7 \end{gathered}
\begin{gathered} \text{Now, } \\ m<1=4x+5 \\ m<1=4\cdot7+5 \\ m<1=28+5 \\ m<1=33 \\ \\ m<2=5x-2 \\ m<2=5\cdot7-2 \\ m<2=35-2 \\ m<2=33 \end{gathered}

User Tornikeo
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