Question

A wire transfers 15.0 C. How many electrons pass through the wire?

Answer 1

Given,

The total charge transferred, Q=15.0 C

The charge of one electron is e=1.6×10⁻¹⁹ C

Thus the number of electrons in 15.0 C is given by,

`N=(Q)/(e)`

On substituting the known values,

`\begin{gathered} N=(15)/(1.6*10^(-19)) \\ =9.38*10^(19) \end{gathered}`

Therefore the number of electrons that pass through the wire is 9.38×10¹⁹