We have the following function

So, in order to get 5 points, we need to put some values into variable x and obtain the y-values. If you substitute x=0 into the function, we have

so we have obtained the point (0,1).
Similarly, if we choose x=0.5, we have

Now, for x=1, we get

For x=2, we get

for x=3, we obtain

and for x=-1, we have

Then, we can to construct the following table:
By means of these coordinate points, the graphs is: