Question

use a standard normal distribution table to find the percentage of area above the standard normal curve that is specified above Z= 1.37

Answer 1

The z-score,x, will give the percentage between z = 0 and z = 1.37.

Therefore percentage above z = 1.37 will be given by

`\text{ the percentage above (z = 1.37) }=\text{ 50\% - (z-score betw}een\text{ 0 and 1.37)}`

Hence,

the percentage = 50% - (41.47)% = 8.53 %

Hence, the percentage of the area above the standard normal curve that is specified above Z= 1.37​ is 8.53 %