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Write an equation for the line perpendicular to the given line that contains Q. Q(9,-4);y= 1/ 2 x+3

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the original line is y = (1/2)x + 3

its slope is m = 1/2

the perpendicular line would have an slope of -1/m which is -2

if we use the perpendicular line slope, it's equation would be:

y = -2x + b,

using Q(9,4): 4 = -2(9) + b = -18 + b

b = 4 + 18 = 22

so the perpendicular line is:

y = - 2x + 22

User Alex Park
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