Question

Write the trigonometric form of the complex number. (Let 0 ≤ < 2.)1 − √3iradical 3i

Answer 1

the answer to your question is i am pretty sure 26

Answer 2

We have the following number:

`1-\sqrt[]{3}i`

and we have:

`a=1,b=-\sqrt[]{3}`

And we can write the trigonometric form as:

`r(\cos \theta+i\sin \theta)`

the radius is:

`r=\sqrt[]{(1)^2+(-\sqrt[]{3})^2}=\sqrt[]{4}=2`

The angle is:

`\theta=\tan ^(-1)(\frac{-\sqrt[]{3}}{1})=(5\pi)/(3)`

Then the answer is:

`2\lbrack\cos ((5\pi)/(3))+i\sin ((5\pi)/(3))\rbrack`