1 Answer

Philask · Answer 1 · 2023-09-12T07:39:35+0000

We are asked to determine a polynomial that has the following roots:

$1+\sqrt[]{2},2-i$

As roots. We will use a polynomial of degree 4 that has the roots:

$1\pm\sqrt[]{2},2\pm i$

This means that the factors of the polynomials are:

$(x-(1+\sqrt[]{2})(x-(1-\sqrt[]{2}))(x-(2-i))(x-(2+i))$

Now we must expand the given factor in order to get a polynomial of rational coefficients. First, we will take the two first products:

$(x-(1+\sqrt[]{2})(x-(1-\sqrt[]{2}))$

Now we will reassociate terms inside each parenthesis:

$((x-1)-\sqrt[]{2})((x-1)+\sqrt[]{2}))$

Now we apply the distributive law using the associated terms:

$(x-1)^2+\sqrt[]{2}(x-1)-\sqrt[]{2}(x-1)-(\sqrt[]{2})^2$

Simplifying:

Therefore, the first two products can be replaced by the term we just found:

Now we take the third and fourth products:

Now we reassociate the terms:

Now we apply the distributive law:

Simplifying we get:

Now we can replace this for the third and fourth products:

Now we solve the squares in each parenthesis:

Adding like terms:

Now we apply the distributive property:

Adding like terms we get:

And thus we get the desired polynomial.

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