Please see the image and help with this homework problem. thank you!

Question

asked Jan 7, 2023 161k views

1 Answer

Lamma · Answer 1 · 2023-01-13T11:42:09+0000

we have the function

$E=\sin (\pi)/(14)t$

Part a

For t=7

substitute in the given function

$\begin{gathered} E=\sin (\pi)/(14)7 \\ E=1 \end{gathered}$

For t=14

$\begin{gathered} E=\sin (\pi)/(14)14 \\ E=0 \end{gathered}$

For t=21

$\begin{gathered} E=\sin (\pi)/(14)21 \\ E=-1 \end{gathered}$

For t=28

$\begin{gathered} E=\sin (\pi)/(14)28 \\ E=0 \end{gathered}$

For t=35

$\begin{gathered} E=\sin (\pi)/(14)35 \\ E=1 \end{gathered}$

Observation: The values of E varies from -1 to 1, including the zero

Part B

Remember that

The Period goes from one peak to the next

so

Period=2pi/B

B=pi/14

Period=(2pi)/(pi/14)=2pi*14/pi=28