In general, we can translate a function c units to the right by changing its argument this way:

So, if we translate log(x) one unit to the right, we will get:

Now, in general, when we translate a function f(x) c units downwards, we obtain a new function, this is:

Then, in our case, we have already translated the function one unit to the right, after applying the translation downwards, we get:

This is the function once we have transformed it
Finally, we need the graph that matches this equation, for this look at the value of x=2

The graph must contain the point (2,-2). Thus, only the graph on the right top corner can be the graph of the function. The graph on the right top corner is the answer