Given data:
1. plain croissants
2. cherry croissants
3. chocolate croissants
4. almond croissants
5. apple croissants
6. brocolli
23 croissants must be chosen
8 are already chosen (at least 5 chocolate croissants and 3 almond croissants)
15 more to select out from the 6 types of croissants
Find: number of ways to select the remaining 15 croissants
Solution:
Selecting the types of croissants can be done in any order, hence, order doesn't matter here. We are dealing with combination.
![(6+15-1)C15=20C15=15,504](https://img.qammunity.org/2023/formulas/mathematics/college/fjy4dqnn49sb2tbo2wl6x59s1yoled5rdq.png)
Hence, there 15, 504 ways to choose 23 croissants with at least five chocolate croissants and at least three almond croissants.