Question

.A scientist uses a submarine to study ocean life.She begins at sea level, which is an elevation of o feet.She descends for 106 seconds at a speed of persecond.• She then travels directly up for 64 seconds at a speed of 1.9 feet persecond.4-5 feetAt this point, what is her elevation, in feet?

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

initial point (sea level) = 0 ft

final elevation = ?

Step 02:

point 1:

0 feet

point 2: descends

106 s ===> 4.5 ft/s

distance = 4.5 ft/s * 106 s = 477 ft

point 3: up

64 s ===> 1.9 ft/s

distance = 1.9 ft/s * 64 s = 121.6 ft

final elevation = point 1 - point 2 (descends) + point 3 (up)

final elevation = 0ft - 477ft + 121.6ft

= -355.4ft

The answer is:

The final elevation is -355.4ft