Question

What will the volume of a gas at 273K be if I have 1 mole of the gas at 1 atm?

Answer 1

`22.386L`

Explanations:

In order to get the required volume of the gas, we will use the ideal gas equation expressed as:

`PV=\text{nRT}`

P is the pressure of the gas (in atm)

V is the volume of the gas (in L)

n is the number of moles

R is the Gas constant

T is the temperature of the gas

Given the following parameters:

`\begin{gathered} P=1\text{atm} \\ T=273K \\ n=1\text{mole} \\ R=0.082Latm/moleK \\ V=\text{?} \end{gathered}`

Substitute the given parameters into the formula to get the volume:

`\begin{gathered} V=\frac{\text{nRT}}{P} \\ V=\frac{1\cancel{\text{mole}}*0.082\frac{L\cdot\cancel{\text{atm}}}{\cancel{\text{molK}}}*273\cancel{K}}{1\cancel{\text{atm}}} \\ V=(1*0.082L*273)/(1) \\ V=22.386L \end{gathered}`

Hence the volume of a gas at 273K be if I have 1 mole of the gas at 1 atm is 22.386L