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Points A, B, C, and D are on circle O, as shown.

User Wei Yang
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1 Answer

3 votes

Given data:

The given figure of the circle.

The angle DCA is,


\begin{gathered} \angle DCA=(1)/(2)\angle AOD \\ =(1)/(2)(114^(\circ)) \\ =57^(\circ) \end{gathered}

BD is diameter , it means the angle BCD is 90 degrees, the angle DBC is,


\begin{gathered} \angle DBC=90^(\circ)-40^(\circ) \\ =50^(\circ) \end{gathered}

The angle BOC is,


\begin{gathered} \angle BOC=180^(\circ)-2\angle\text{OBC} \\ =180^(\circ)-2\angle DBC \\ =180^(\circ)-2(50^(\circ)) \\ =80^(\circ) \end{gathered}

Thus, the third option is correct.

User Ayaka
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3.7k points