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Exercises 12.3 Complete the following: 1. Complete the squares for each quadratic, list the center labeling its translated center: (g) x^2 + y^2 + 4x = 0

User RevJohn
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EXPLANATION

Considering the equation x^2 + y^2 + 4x = 0

As we already know, the circle equation with a radius r, centered at (a,b) is:


(x-a)^2+(y-b)^2=r^2

Rewrite x^2 + y^2 + 4x = 0 in the form of the standard circle equation:

Group x-variables and y-variables together:


(x^2+4x)+y^2=0

Convert x to square form:


(x^2+4x+4)+y^2=4

Convert to square form:


(x+2)^2+y^2=4

Refine 4:


(x+2)^2+y^2=4

Rewrite in standard form:


(x-(-2))^2+(y-0)^2=2^2

Therefore the circle properties are:

center: (a,b)=(-2,0) radius: r=2

Finally, drawing the graph of the equation:

Exercises 12.3 Complete the following: 1. Complete the squares for each quadratic-example-1
User Joseph Ditton
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