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In ADEF, DF = 16 and m

In ADEF, DF = 16 and m-example-1
User Shaz
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1 Answer

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Let's put more details in the given figure to better understand the problem:

It appears that the triangle is an Isosceles Triangle. Because of this, the legs of the triangle should be congruent.

Let's determine the length of its leg using the Sine Function: Let, x = the length of the leg.


\text{ Sine }\Theta\text{ = }\frac{\text{ Opposite}}{\text{ Hypotenuse}}
\text{ Sine }45^(\circ)\text{ = }\frac{\text{ x}}{\text{ 1}6}
\text{ (16)Sine }45^(\circ)\text{ = x}
\text{ x = (16)Sine }45^(\circ)
\text{ x = (16)(}\frac{1}{\sqrt[]{2}})\text{ = }\frac{16}{\sqrt[]{2}}\text{ = }\frac{\text{ 16 }\cdot\text{ }\sqrt[]{2}}{\sqrt[]{2}\text{ }\cdot\text{ }\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}
\text{ x = 8}\sqrt[]{2}

Therefore, the length of its leg is 8√2

In ADEF, DF = 16 and m-example-1
User Chanlito
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