Answer
(a) Exact lateral area:

Approximate lateral area:

(b) Exact total area:

Approximate total area:

(c) Exact volume:

Approximate volume:

Explanation
Lateral area of a cone formula

where r is the radius and h is the height of the cone.
Substituting h = 5 m, and r = 3 m, we get:

Total area of a cone formula

Substituting with the previous result and r = 3 m, we get:

Volume of a cone formula

Substituting h = 5 m, and r = 3 m, we get:
