Question

Find the length of WS br />A.132.59
B.134.24
C.21.26
D.3.33

Answer 1

Given the shown triangle

Using cosine laws

`c^2=a^2+b^2-2abcos(C)`
`c^=√(a^2+b^2-2abcos(C))`

where

b=

`b=(21sin(81))/(sin(9))`
`b=132.59`

then

`c=√(a^2+b^2-2abcos(C))`
`c=√(21^2+132.59^2-2(21)(132.59)cos(90))`
`c=134.24`

WS= 134.24