Question

The amount of heat required to raise 200 g of aluminum from -20 to 45 degrees celsius if its specific heat is 0.21 J/g-°C is:O 17.3JO 2730O 1053O 38.13

Answer 1

In this question, we have a situation in which we have to use the Calorimetry formula, which is how much heat was released or absorbed (in Joules), after we had a change in temperature of a compound. The formula for this Calorimetry question is:

Q = mcΔT

Where:

Q = is energy as Heat

m = mass in grams, 200 grams

c = is the specific heat capacity, 0.21 J/g°C

ΔT = the change in temperature, calculated as Final Temperature - Initial T

45 - (- 20) = 65

Now we add these values into the formula:

Q = 200 * 0.21 * 65

Q = 2730 Joules of heat, letter B