Question

Triangle PQR has vertices P(–3, –1), Q(–3, –3), and R(–6, –2). The triangle is rotated 90° counterclockwise using the origin as the center of rotation. Which graph shows the image, triangle P’Q’R’? On a coordinate plane, triangle P prime Q prime R prime has points (negative 3, negative 1), (negative 3, negative 3), (negative 6, negative 2). On a coordinate plane, triangle P prime Q prime R prime has points (negative 1, 3), (negative 3, 3), (negative 2, 6). On a coordinate plane, triangle P prime Q prime R prime has points (1, negative 3), (3, negative 3), (2, negative 6). On a coordinate plane, triangle P prime Q prime R prime has points (3, negative 1), (3, negative 3), (6, negative 2).

Answer 1

The coordinates of two vertices are given

P(3,3)

Q(3,1)

Assuming that PQ and QR are the legs of equal length, the distance between Q and R must be the same as the distance between P and Q

d = √[(3-3)² + (3-1)²

d = 2

Therefore, the coordinates of P is

(5,1)

Explanation: