Question

A hawk's eye has a diameter of0.00620 m. What is the closestdetail it could possibly resolve at50.0 m, using 525 nm light?[?] m

Answer 1

Given:

• Diameter, D = 0.00620 m

,

• Wavelength, λ = 525 nm

,

• Distance, x = 50.0 m

Let's find the closest detail it could possibly resolve.

Let's apply the Angular separation formula:

`\theta=(1.22\lambda)/(D)`

Thus, we have:

`\begin{gathered} \theta=(1.22*525*10^(-9))/(0.00620) \\ \\ \theta=(6.405*10^(-7))/(0.00620) \\ \\ \theta=1.033*10^{-4\text{ }}rad \end{gathered}`

Now, to find the distance which is the closest detail, we have:

`\begin{gathered} d=\theta *x \\ \\ d=1.033*10^(-4)*50.0 \\ \\ d=0.005165\text{ m} \end{gathered}`

The closest detail it could possibly resolve is at 0.005165 meters

• ANSWER:

0.005165 m