Question

How do you write an equation of the line that passes through the point (6,1) and the slope m=-3

Answer 1

The equation of the line that passes through the point (6,1) and the slope m=-3​ is;

`y=3x-17`

Step-by-step explanation:

Given the line with slope;

`m=3`

And passes through the point;

`(6,1)`

Using the point-slope form of linear equation;

`y-y_1=m(x-x_1)`

Substituting the values of the slope and the given point;

`y-1=3(x-6)`

Above is the point-slope form of the equation.

solving further to get the slope-intercept form of the equation we have;

`\begin{gathered} y-1=3x-18 \\ y=3x-18+1 \\ y=3x-17 \end{gathered}`

Therefore, the equation of the line that passes through the point (6,1) and the slope m=-3​ is;

`y=3x-17`