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12 votes
12 votes
SA = 2tr2 + 2trh (Use 3.14 for .) How much metal is needed to create a cylindrical can with a height of 5 inches and a base diameter of 3 inches? square inches Do NOT round your answer.​

User Billyjov
by
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2 Answers

12 votes
12 votes

Answer:

Answer: 61.23 / {I'm right trust me Acellus 2022}

Explanation:

how much metal is needed to create a cylindrical can with a height of 5 inches and a base diameter of 3 inches

User JCx
by
2.8k points
5 votes
5 votes

Answer:


SA=61.26\ \text{inches}^2

Explanation:

The surface area of a cylinder is given by :


SA=2\pi r^2+2\pi rh

Where

r is radius and h is height of the cylinder

We have, h = 5 inches and r = 3/2 = 1.5 inches

Put all the respected values.


SA=2\pi * (1.5)^2+2\pi * 1.5* 5\\\\SA=61.26\ \text{inches}^2

So, the surface area of the cylinder is equal to
61.26\ \text{inches}^2.

User ZviBar
by
2.8k points