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Which function does not have a domain of all real numbers?Select one:I ofestionO a. f(x) = (x - 1O b. f(x) = -73 + 4xO c. f(x) = -|x - 5] + 1O d. f(x) = x+6-1 3х

User Silk
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1 Answer

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We need to find which function doesn't have a domain for all real numbers.

for a.


f(x)=\sqrt[]{x}-1

When we have a square root " The domain is all values of x results in a radicand that is equal to greater than zero"

So the domain, in this case, is x≥0.

b.


-x^3+4x

x can take any real number because we don't have restrictions.

c.


-\text{ l x-5l +1}

We have an absolute value but x can be any real number.

d.


(1)/(2)\sqrt[3]{x+6}

The cube root can be used for real numbers, so the function can take for x all real numbers.

The only function that doesn't have a domain of all real numbers is option a.

User Damnum
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