We need to find which function doesn't have a domain for all real numbers.
for a.
![f(x)=\sqrt[]{x}-1](https://img.qammunity.org/2023/formulas/mathematics/college/rzppptk329480eet3iot9qr8lws9l8egt8.png)
When we have a square root " The domain is all values of x results in a radicand that is equal to greater than zero"
So the domain, in this case, is x≥0.
b.

x can take any real number because we don't have restrictions.
c.

We have an absolute value but x can be any real number.
d.
![(1)/(2)\sqrt[3]{x+6}](https://img.qammunity.org/2023/formulas/mathematics/college/v27ch0b3rpourawx3qvketqigrr6suyzbq.png)
The cube root can be used for real numbers, so the function can take for x all real numbers.
The only function that doesn't have a domain of all real numbers is option a.