Answer:
The equation of the line with the given points is:
![y=-(1)/(5)x](https://img.qammunity.org/2023/formulas/mathematics/college/vrck2pgwl32z7ofjjr3p7c4ouvryqn2vlq.png)
Step-by-step explanation:
Given the coordinates (0, 0) and (10, -2)
The equation of a line is in the form:
y = mx + b
Where m is the slope and b is the y-intercept.
The slope from the given coordinates is:
![\begin{gathered} m=(-2-0)/(10-0) \\ \\ =-(2)/(10)=-(1)/(5) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/tg180kqo3vqn28y6sm4hx26e4bxawdxzzm.png)
The equation is now in the form:
![y=-(1)/(5)x+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/h7hcfb3sk2dqigzea1upqxorufngljm42h.png)
Using the point (10, -2) to find b, replace x by 10 and y by -2 in the last equation
![\begin{gathered} -2=-(1)/(5)(10)+b \\ \\ -2=-2_{_{_{_{_{_{_{_{}}}}}}}}+b \\ b=0 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gq7oqi6prh5bdje1aptxb0tk73k35b1tn5.png)
Therefore, the equation of the line is:
![y=-(1)/(5)x](https://img.qammunity.org/2023/formulas/mathematics/college/vrck2pgwl32z7ofjjr3p7c4ouvryqn2vlq.png)