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37 votes
37 votes
A car travels along a straight road to the east for

100 meters in 4 seconds, then has to turn around

and goes back west for 50 meters in 1 second.

Determine average speed and average velocity.

User Piergiovanni
by
3.0k points

1 Answer

9 votes
9 votes

Answer: 90 m/s, 70 m/s

Step-by-step explanation:

Given

A car travels 100 m east for 4 seconds and then turn around

goes back west for 50m in 1 sec

Distance traveled in the east is
100* 4=400\ m

Distance traveled in the west is
50* 1=50\ m

Total distance
=400+50=450\ m

total displacement
=400-50=350\ m

total time
t=4+1=5\ s

Average speed


\Rightarrow s_(avg)=\frac{\text{distance}}{\text{time}}=(450)/(5)\\\\\Rightarrow s_(avg)=90\ m/s

Average velocity


\Rightarrow v_(avg)=\frac{\text{displacement}}{\text{time}}=(350)/(5)\\\\\Rightarrow v_(avg)=70\ m/s

User Seveninstl
by
2.6k points