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The perimeter of a rectangle is 44 meters and the length is 10 meters more than twice the width. Find the dimensions.18 meters and 4 meters6 meters and 9 meters5 meters and 9 meters6 meters and 16 meters

1 Answer

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Given:

The perimeter of a rectangle is 44 meters.

The length is 10 meters more than twice the width.

Required:

To find the dimensions.

Step-by-step explanation:

The perimetero of rectangle formula is


P=2(L+W)

Let x be the width.

The length is 10 meters more than twice the width.

So


L=2x+10

Now


\begin{gathered} P=2(2x+10+x) \\ \\ 44=4x+20+2x \\ \\ 44=6x+20 \\ \\ 6x=44-20 \\ \\ 6x=24 \\ \\ x=(24)/(6) \\ \\ x=4m \end{gathered}

Here the width is 4m.

Now the length is


\begin{gathered} L=2(4)+10 \\ =8+10 \\ =18m \end{gathered}

Final Answer:

18 meters and 4 meters.

User Egoskeptical
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