Step-by-step explanation:
According to the problem 0.2916 g of water were produced, so we have to find the number of moles of H in that sample of water. First we will convert those grams into moles using the molar mass of water.
molar mass of H = 1.01 g/mol
molar mass of O = 16.00 g/mol
molar mass of H₂O = 2 * 1.01 g/mol + 1 * 16.00 g/mol
molar mass of H₂O = 18.02 g/mol
moles of H₂O = 0.2916 g * 1 mol/(18.02 g)
moles of H₂O = 0.01618 moles
One molecule of H₂O contains two atoms of H. So 1 mol of H₂O molecules will contain 2 moles of H atoms. We can use that relationship to find the answer to our problem.
1 mol of H₂O = 2 moles of H
moles of H = 0.01618 moles of H₂O* 2 moles of H/(1 mol of H₂O)
moles of H = 0.03236 mol
Answer: 0.03236 mol of H atoms are present in the water produced.